Equation of a pair of straight lines passing through the origin
y = m1x, y = m2x
(y -m1x)(y -m2x) = 0
i.e. m1m2x2- (m1 + m2)xy + y2 = 0 ---(**)
   -- a homogenous equation of the second degree in x and y
The standard form of a pair of straight lines is
ax2 + 2hxy + by2 = 0  ---(*)
If (*) and (**) are equivalent
if
m1m2 and  m1 + m2
If the lines are perpendicular, then m1m2 = 1 i.e. a + b = 0
And the anglebetween the two lines is given by
tan
The two lines are the same
h2-ab = 0
perpendicular
a + b = 0
Consider ax2 + 2hxy + by2 = 0  ---(*)
when b0
y
i.e. The equation of the two straight lines passing through the origin.
(I) If b = 0 and a = 0 and h0, (*)  2hy = 0 which gives the lines x = 0 and y = 0
(II) If b = 0 and a0, then (*) becomes  ax2 + 2hxy = 0 x(ax + 2hy) = 0 and represents the lines x = 0 and ax + 2hy= 0
(III) If b0, then the two lines are real if (*)  2hy = 0 which gives the lines x = 0 and y = 0
If b0, then the two lines are
real if
h2 - ab > 0 i.e.  h2 > ab
coincident if
h2 = ab
the point (0,0) OR imaginary if
h2 -ab < 0 i.e.  h2 < ab