Conormail points on the rectangular hyperbola xy=c2
The normal at [t] passes through (X, Y) if
tX -Y/t = c(t2-
i.e.  if ct4-t3X + tY -c = 0
ct4-Xt3 + Yt-c = 0
The root of t1, t2, t3, t4 of this quartic equation are the 4 conormal points
and  t1t2t3t4 = -1
and   y1y2y3y4 = (ct1)(ct2)(ct3)(ct4) = c4t1t2t3t4 = - c4
and  X/c = (t1 + t2 + t3 + t4X = c(t1+ t2 + t3 + t4)
Y/c = -(t1t2 t3 + t1t2t4 + t1t3t4 + t2t3t4 )
Y = - c(t1t2t3t4) = c
t1t2t3t4 = -1