Coaxal Circles
A system of circles having the same radical axis are said to form a coaxal system.
Condsider the equation of the radical axis
2(g - g')x + 2(f - f')y + C - C' = 0
(a) Let the centre of the circles lie on the x-axis.
(b) Let the radical axis be the y-axis
f = f' = 0 ,  x = 0,  C - C' = 0
then 
C = C'
Hence, the circles with the centre at the x-axis is of the form
x2 + y2 + 2x + C = 0
where C is a constant and is a parameter,
have the y-axis as the radical axis 
each value of determines a circle of the coaxal system.
The circles  x2 + y2 + 2x + C = 0
cut the radical axis x = 0 at points where y2 + C = 0
(a) if C < 0
there are two real points of intersection 
(0, ) and (0, -)
(b) if C = 0, y = 0
each circle touches the axis at (0,0)
(c) if C > 0
no point of intersection.
Consider the radius of the circles
2 - C = r2                r
Where r = 0 the circle is a point circle 2 = C, 
if C < 0 no point circle
if C = 0 = 0 point circle is at the origin
if C < 0 two point circles at (,0) , (,0)
Circle : x2 + y2 + 2x + C = 0     Limiting points : (, 0)
The circle x2 + y2 + 2g'x + 2f'y + C' = 0
passes through the limiting point (, 0)
if  C2g'+ C' = 0
if  C + C' = 0 and g' = 0
circles of the form x2 + y2 + 2x + C = 0 ---(*)
     passes through the limiting point of the coaxal system given by
x2 + y2 + 2x + C = 0
(a) (*) gives another coaxal system of circles having centre on the radical axis of the first system and the radical axis being the x-axis.
(b) If 2gg' + 2ff' - (C + C') = 0
Hence, any 2 circles search from either system are orthogonal.